document.write( "Question 1193648: A scientist mixes water (containing no salt) with a solution that contains 55% salt. She wants to obtain 220 ounces of a mixture that is 30% salt. How many ounces of water and how many ounces of the 55% salt solution should she use?\r
\n" ); document.write( "\n" ); document.write( "Water= Ounces
\n" ); document.write( "Salt Solution= Ounces
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Algebra.Com's Answer #825690 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "x = amount of the 55% salt solution, in ounces\r
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\n" ); document.write( "\n" ); document.write( "It isn't clear if your teacher is referring to dry ounces or fluid ounces. Though the math will lead to the same result either way.\r
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\n" ); document.write( "\n" ); document.write( "If we had x ounces of the 55% salt solution (i.e. 55% salt, the rest water), then we have 0.55x ounces of pure salt.\r
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\n" ); document.write( "\n" ); document.write( "We aim to have 220 ounces of total mixture, after adding in the water to dilute things. We want to dilute to a 30% salt concentration.\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "(amount of pure salt)/(total mix) = salt concentration
\n" ); document.write( "(0.55x)/(220) = 0.30\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 220, then divide both sides by 0.55 as the steps show below
\n" ); document.write( "(0.55x)/(220) = 0.30
\n" ); document.write( "0.55x = 220*0.30
\n" ); document.write( "0.55x = 66
\n" ); document.write( "x = 66/0.55
\n" ); document.write( "x = 120
\n" ); document.write( "We need 120 ounces of the 55% salt solution
\n" ); document.write( "This leaves 220-x = 220-120 = 100 ounces of pure water\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "Water = 100 ounces
\n" ); document.write( "Salt solution = 120 ounces
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