document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193653>Question 1193653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that The lengths of pregnancies are normally distributed with a mean of 271 days and a standard deviation of 10 days. how do I find the percentage of pregnancies that are longer than 254 days? for my immediate computations used for or more decimal places give my final answer to two decimal places. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825689 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( ">(254-271)/10<BR>\n" );
document.write( "or >-1.7<BR>\n" );
document.write( "=0.9554 or 0.96<BR>\n" );
document.write( "This makes sense, because from -2 sd rightward, the probability is about 97.5%. This isn't quite as much to the left as -2 sd but close. </SPAN>\n" );
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