document.write( "Question 1193615: Consider the following figure where △ABC ~ △DBE.
\n" ); document.write( "AC = 6, DE = 4, CB = 5
\n" ); document.write( "Find:EB \n" ); document.write( "
Algebra.Com's Answer #825674 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Pay very close attention to the order of the letters in △ABC ~ △DBE.
\n" ); document.write( "The ordering tells us how the letters pair up.\r
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\n" ); document.write( "\n" ); document.write( "A and D are the 1st letters of ABC and DBE respectively
\n" ); document.write( "B and B are the 2nd letters of ABC and DBE respectively
\n" ); document.write( "C and E are the 3rd letters of ABC and DBE respectively\r
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\n" ); document.write( "\n" ); document.write( "From there we know that
\n" ); document.write( "AC pairs with DE because both involve the 1st and 3rd letters
\n" ); document.write( "CB pairs with EB because both involve the 3rd and 2nd letters\r
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\n" ); document.write( "\n" ); document.write( "Now we can set up a proportion, cross multiply and solve for EB,
\n" ); document.write( "AC/DE = CB/EB
\n" ); document.write( "6/4 = 5/EB
\n" ); document.write( "6*EB = 4*5
\n" ); document.write( "6*EB = 20
\n" ); document.write( "EB = 20/6
\n" ); document.write( "EB = (10*2)/(3*2)
\n" ); document.write( "EB = 10/3
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