document.write( "Question 1193642: A piece of Capillary tubing was Calibrated in the Following Manner. A clean Sample of Mass 3.247 g . A thread of Mercury, drawn into the tube a length of 23.75 mm as observed under microscope . The mass of Tube and Mercury was 3.489 g. The Density of Mercury is 13.60 g/cm^3 .Assuming that the capillary bore is a uniform cylinder, find the diameter of the bore if the volume of a cylindrical object is V= pie r^2 h \n" ); document.write( "

Algebra.Com's Answer #825672 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "The mass of the Mercury is the product of the bore volume by the density \"d\" of Mercury\r\n" );
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document.write( "    3.247 = ,\r\n" );
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document.write( "or\r\n" );
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document.write( "    3.247 = ,\r\n" );
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document.write( "where 2.375 is the length of  23.75 mm, converted to centimeters.\r\n" );
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document.write( "From the formula,\r\n" );
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document.write( "     =  = 0.032015,\r\n" );
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document.write( "     r =  = 0.1789 cm = 1.789 mm.    \r\n" );
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document.write( "ANSWER. The diameter of the bore is  2r = 2*1.789 mm = 3.578 mm.\r\n" );
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