document.write( "Question 1193591: Find the sum of this series that is not arithmetic or geometric,
\n" ); document.write( "1+2+4+5+7+8....+95+97+98\r
\n" ); document.write( "\n" ); document.write( "can someone help, a few of us have been trying to figure this out, our teacher said its solvable but I don't even know where to start, thankyou
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Algebra.Com's Answer #825650 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "You have received two responses that show two very different ways of solving the problem, both of which are valid.

\n" ); document.write( "Here is a third (still very different) method....

\n" ); document.write( "The sequence is clearly neither geometric nor arithmetic. But we can make it into an arithmetic sequence by pairing the terms:

\n" ); document.write( "1+2=3
\n" ); document.write( "4+5=9
\n" ); document.write( "7+8=15
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\n" ); document.write( "97+98=195

\n" ); document.write( "So the sum is

\n" ); document.write( "3+9+15+...+195

\n" ); document.write( "That is an arithmetic sequence with first term 3, last term 195, and common difference 6. The sum of the sequence is

\n" ); document.write( "(number of terms) times (average of all the terms)

\n" ); document.write( "Since the sequence is arithmetic, the average of all the terms is the average of the first and last: (3+195)/2=99

\n" ); document.write( "The number of terms is

\n" ); document.write( "(last term minus first term), divided by 6, plus 1

\n" ); document.write( "The difference between the first and last terms, divided by the common difference, tells you the number of terms AFTER THE FIRST ONE; that's why you need to add 1 at the end.

\n" ); document.write( "195-3=192; 192/6=32; 32+1=33

\n" ); document.write( "So we have a sequence of 33 terms with an average of 99; the sum is

\n" ); document.write( "33(99)=33(100-1) = 3300-33 = 3267

\n" ); document.write( "ANSWER: 3267

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