document.write( "Question 1193599: How many different “words” can be formed by using all the letters of each of the
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Algebra.Com's Answer #825644 by ikleyn(52781)\"\" \"About 
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document.write( "(a)  5 different letters admit 5! = 5*4*3*2*1 = 120 PERMUTATIONS.\r\n" );
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document.write( "(b)  5 letters, with one letter  \"P\"  of the multiplicity 2 admit  \"5%21%2F2\" = \"120%2F2\" = 60 different arrangements.\r\n" );
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\n" ); document.write( "\n" ); document.write( "On permutations, see the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Introduction to Permutations\r
\n" ); document.write( "\n" ); document.write( "    - PROOF of the formula on the number of Permutations\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-II in this site\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic  \"Combinatorics: Combinations and permutations\". \r
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\n" ); document.write( "\n" ); document.write( "Save the link to this textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-II
\n" ); document.write( "https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson\r
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