document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113502>Question 113502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A community hall has an area of 396 metres squared. A 12 metre by 16 metre rug is placed on the floor so that the width of the floor showing on the four sides is uniform. What is the distance between the rug and the wall ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82564 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 396=(12+2X)(16+2X) <BR>\n" );
document.write( "X BEING THE SPACE BETWEEN THE RUG & THE WALL.<BR>\n" );
document.write( "IT HELPS TO DRAW A DIAGRAM TO CAPTURE THE PROGRAM PICTORALLY.<BR>\n" );
document.write( "396=192+32X+24X+4X^2<BR>\n" );
document.write( "4X^2+56X+192-396=0<BR>\n" );
document.write( "4X^2+56X-204=0<BR>\n" );
document.write( "4(X^2+14X-51)=0<BR>\n" );
document.write( "4(X-3)(X+17)=0<BR>\n" );
document.write( "X-3=0<BR>\n" );
document.write( "X=3 METERS IS THE SPACE BETWEEN THE RUG & THE WALL. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );