document.write( "Question 1193515: Number of letter per day 0 1 2 3 4 5
\n" ); document.write( "Frequency 28 21 6 3 1 1
\n" ); document.write( "Find mode, median,mean,range
\n" ); document.write( "

Algebra.Com's Answer #825545 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Number of letter per day 0 1 2 3 4 5\r
\n" ); document.write( "\n" ); document.write( "Frequency 28 21 6 3 1 1\r
\n" ); document.write( "\n" ); document.write( "Find mode, median, mean, range\r
\n" ); document.write( "\n" ); document.write( "Frequency means you have:
\n" ); document.write( " \"28\" zeros
\n" ); document.write( "\"21\" 1s
\n" ); document.write( "\"6\" 2s
\n" ); document.write( "\"3\" 3s
\n" ); document.write( "\"1\" 4s
\n" ); document.write( "\"1\" 5s\r
\n" ); document.write( "\n" ); document.write( "so your set is:
\n" ); document.write( "\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0%2C%7B%7B%7B0%2C%7B%7B%7B0%2C%7B%7B%7B0%2C%7B%7B%7B0%2C%7B%7B%7B0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\",\"0\", \"1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"1%2C%7B%7B%7B1\",\"1%2C%7B%7B%7B1\",\"1\",\"1\",\"1\",\"1\",\"1\",\"2\",\"2\",\"2\",\"2\",\"2\",\"2\",\"3\",\"3\",\"3\",\"4%2C%7B%7B%7B5+\"=> total number \"n=60\"\r
\n" ); document.write( "\n" ); document.write( "add all and sum is\"+51\"\r
\n" ); document.write( "\n" ); document.write( "recall:\r
\n" ); document.write( "\n" ); document.write( "The \"mean\" is the same as the average value of a data set and is found using a calculation. Add up all of the numbers and divide by the number of numbers in the data set.\r
\n" ); document.write( "\n" ); document.write( "The \"median\" is the central number of a data set. Arrange data points from smallest to largest and locate the central number. This is the median. If there are 2 numbers in the middle, the median is the average of those 2 numbers.\r
\n" ); document.write( "\n" ); document.write( "The \"mode\" is the number in a data set that occurs most frequently. Count how many times each number occurs in the data set. The mode is the number with the highest tally. It's ok if there is more than one mode. And if all numbers occur the same number of times there is no mode.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "mean: is the sum of all the data divided by the count n\r
\n" ); document.write( "\n" ); document.write( "\"mean=51%2F60=0.85\"\r
\n" ); document.write( "\n" ); document.write( "median:
\n" ); document.write( "
\n" ); document.write( "Arrange data values from lowest to highest value
\n" ); document.write( "The median is the data value in the middle of the set
\n" ); document.write( "If there are 2 data values in the middle the median is the mean of those 2 values.\r
\n" ); document.write( "\n" ); document.write( "data values already arranged from lowest to highest value
\n" ); document.write( " as you can see, \r
\n" ); document.write( "\n" ); document.write( "\"median=+1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "mode: is the number in a data set that occurs most frequently\r
\n" ); document.write( "\n" ); document.write( "in your case \"0+\" occurs most frequently (\"28+\"times)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"mode=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Range:
\n" ); document.write( "\"Range=5\" (greatest value in set above)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );