document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193488>Question 1193488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Doris walks 89 feet diagonally across a rectangular field. She then returns to her starting position along the outside of the field. The total distance she walks is 208 feet. What are the dimensions of the field?\r<BR>\n" );
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document.write( "I would assume you could use the Pythagorean theorem for this, but when I tried I did not get an answer that added up to 208. Please explain step-by-step so I can understand how to solve the problem! Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825518 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825518\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the two outside dimensions are x and y, then x+y=208-89=119.  Now, you can give the two outside dimensions as  x and 119-x.  Time next for Pythagorean Theorem Formula, hypotenuse  of 89. </SPAN>\n" );
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