document.write( "Question 1193431: Please help me with the homework.\r
\n" ); document.write( "\n" ); document.write( "A man invests R1000 at a simple interest rate of 10% for a period of 3years
\n" ); document.write( "1.1. How much interest does this man get at the end of the first year?
\n" ); document.write( "1.2. How much interest does he get at the end of the second year?
\n" ); document.write( "1.3. How much interest does he get at the end of the third year?
\n" ); document.write( "1.4. What is the total interest that is earned by two man at the end of the 3years?
\n" ); document.write( "Thanks very much in advance for your help.
\n" ); document.write( "

Algebra.Com's Answer #825454 by Boreal(15235)\"\" \"About 
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I=prt
\n" ); document.write( "=R1000*0.10*1=R100 the first year.
\n" ); document.write( "Since it is simple interest, it is the same the second and the third years.
\n" ); document.write( "That is a total of R300.
\n" ); document.write( "I=R1000*0.10*3=R300
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