document.write( "Question 1193413: Peter has been saving his loose change for several days. When he counted his quarters and dimes, he found they had a total value $15.80. The number of quarters was nineteen more than three times the number of dimes. How many quarters and how many dimes did Peter have?\r
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Algebra.Com's Answer #825447 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "If your mental arithmetic is good, you can solve the problem informally using exactly the same calculations used in the formal algebraic solution shown by the other tutor.

\n" ); document.write( "(1) The total value is $15.80
\n" ); document.write( "(2) Take away the \"extra\" 19 quarters. $15.80 - 19($0.25) = $15.80 - $4.75 = $11.05
\n" ); document.write( "(3) Group the remaining coins in groups of 3 quarters and 1 dime, each with a total value of 3($0.25)+1($0.10)=$0.85
\n" ); document.write( "(4) The number of those groups needed to make the remaining $11.05 is $11.05/$0.85 = 13

\n" ); document.write( "So in those 13 groups there are a total of 39 quarters and 13 dimes; now add back in the other 19 quarters to get the final answer of 39+19=58 quarters and 13 dimes.

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