document.write( "Question 1193397: Fifty percent of midsize manufacturers planned to have management representative visit Canada and Mexico to take advantage of opportunities created by the North American Free Trade Agreements. An export-import group in Toronto , Canada , has invited 20 US midsize manufacturers to participate in the conference to explore trade opportunities. What is the probability that 12 or more of these manufacturers will send representatives? \n" ); document.write( "
Algebra.Com's Answer #825419 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 0.251722 (approximate)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=========================================================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of successes = number of companies that send a representative \n" ); document.write( "n = sample size = 20 \n" ); document.write( "p = probability a company sends a representative = 50% = 0.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B(x) = binomial probability \n" ); document.write( "B(x) = (n C x)*(p)^(x)*(1-p)^(n-x) \n" ); document.write( "B(x) = (20 C x)*(0.5)^(x)*(1-0.5)^(20-x) \n" ); document.write( "B(x) = (20 C x)*(0.5)^(x)*(0.5)^(20-x) \n" ); document.write( "The n C x refers to the nCr combination formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in x = 12 \n" ); document.write( "B(x) = (20 C x)*(0.5)^(x)*(0.5)^(20-x) \n" ); document.write( "B(12) = (20 C 12)*(0.5)^(12)*(0.5)^(20-12) \n" ); document.write( "B(12) = (125,970)*(0.5)^(12)*(0.5)^(8) \n" ); document.write( "B(12) = 0.120134 approximately \n" ); document.write( "This is the approximate probability exactly twelve companies send a representative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Repeat for x = 13 \n" ); document.write( "B(x) = (20 C x)*(0.5)^(x)*(0.5)^(20-x) \n" ); document.write( "B(13) = (20 C 13)*(0.5)^(13)*(0.5)^(20-13) \n" ); document.write( "B(13) = (77,520)*(0.5)^(13)*(0.5)^(7) \n" ); document.write( "B(13) = 0.073929 approximately \n" ); document.write( "This is the approximate probability exactly thirteen companies send a representative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These steps are repeated for x = 14, x = 15, all the way up to x = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll let you do those steps, but you should get these approximate results: \n" ); document.write( "B(14) = 0.036964 \n" ); document.write( "B(15) = 0.014786 \n" ); document.write( "B(16) = 0.004621 \n" ); document.write( "B(17) = 0.001087 \n" ); document.write( "B(18) = 0.000181 \n" ); document.write( "B(19) = 0.000019 \n" ); document.write( "B(20) = 0.000001 \n" ); document.write( "All of which are approximate to 6 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The last step is to add B(12), B(13), all the way up to B(20) \n" ); document.write( "You should get 0.251722 when doing so. \n" ); document.write( "There's about a 25.1722% chance of twelve or more companies sending a representative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's one free calculator to check your work \n" ); document.write( "https://calculator-online.net/binomial-distribution-calculator/ \n" ); document.write( "there are tons of other free options out there as well. \n" ); document.write( " \n" ); document.write( " |