document.write( "Question 1193384: Hi
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document.write( "there were 2222 participants in halls A B and C. During the first interval,3/5 in A went to B .During the second interval, 2/3 of B went over to C. During the last interval,half of C left. In the end there were twice as many participants in C as in B and twice as many participants in B as in A.
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document.write( "How many were in B at first.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #825390 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let the beginning numbers in the halls be A, B, and C. \n" ); document.write( "In the first interval, 3/5 of A move to B (2/5 stay in A) \n" ); document.write( "# in A: (2/5)A \n" ); document.write( "# in B: B+(3/5)A \n" ); document.write( "# in C: still C \n" ); document.write( "In the second interval, 2/3 of those in B moved to C (1/3 remained in B) \n" ); document.write( "# in A: (2/5)A \n" ); document.write( "# in B: (1/3)(B+(3/5)A) = (1/3)B+(1/5)A \n" ); document.write( "# in C: C+(2/3)(B+(3/5)A) = C+(2/3)B+(2/5)A \n" ); document.write( "In the third interval, half of those in C left (half remained) \n" ); document.write( "# in A: (2/5)A \n" ); document.write( "# in B: (1/3)B+(1/5)A \n" ); document.write( "# in C: (1/2)C+(1/3)B+(1/5)A \n" ); document.write( "In the end, the number in B was twice the number in A: \n" ); document.write( "(1/3)B+(1/5)A=2((2/5)A) \n" ); document.write( "(1/3)B=(3/5)A \n" ); document.write( "B=(9/5)A \n" ); document.write( "And in the end, the number in C was twice the number in B: \n" ); document.write( "(1/2)C+(1/3)B+(1/5)A=2((1/3)B+(1/5)A) \n" ); document.write( "(1/2)C=(1/3)B+(1/5)A=(1/3)((9/5)A)+(1/5)A=(3/5)A+(1/5)A=(4/5)A \n" ); document.write( "C=(8/5)A \n" ); document.write( "The total number of students was 2200: \n" ); document.write( "A+B+C=2200 \n" ); document.write( "A+(9/5)A+(8/5)A=2200 \n" ); document.write( "(22/5)A=2200 \n" ); document.write( "A=500 \n" ); document.write( "B=(9/5)A=900 \n" ); document.write( "C=(8/5)A=800 \n" ); document.write( "ANSWER: The number in B at the start was 900 \n" ); document.write( "CHECK: \n" ); document.write( "start (A,B,C) = (500,900,800) \n" ); document.write( "after first interval: (200,1200,800) \n" ); document.write( "after second interval: (200,400,1600) \n" ); document.write( "after third interval: (100,400,800) \n" ); document.write( " \n" ); document.write( " |