document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193313>Question 1193313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Analyze the problem and Sketch the figure of the given situation.<BR>\n" );
document.write( "A. For y=ln2x , determine the equation of a tangent line parallel to 2x-3y+1=0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825376 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For y=ln2x , determine the equation of a tangent line parallel to 2x-3y+1=0.<BR>\n" );
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document.write( "If you mean y = ln(2x):<BR>\n" );
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document.write( "Find the slope of the given line, m<BR>\n" );
document.write( "m = 2/3<BR>\n" );
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document.write( "Find the slope of y = ln(2x)<BR>\n" );
document.write( "Find the 1st derivative<BR>\n" );
document.write( "y' = (1/2x)*2 = 1/x is the slope at any point (x,ln(2x))<BR>\n" );
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document.write( "1/x = 2/3<BR>\n" );
document.write( "x = 3/2, y = ln(3)<BR>\n" );
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document.write( "y-ln(3) = (2/3)*(x - 1.5) </SPAN>\n" );
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