document.write( "Question 1193292: 13 people want to play a game. There can be any number of people on each team but only 2 teams total. How many combinations of teams can be formed? \r
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document.write( "I need steps and answer using nCr formula. \n" );
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Algebra.Com's Answer #825368 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Label the two teams as A and B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Imagine we have 13 slots to represent the players. Each slot will be labeled either A or B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we have 13 slots, and two choices per slot, this gives 2^13 = 8192 different ways to assign each player to a certain team. You can think of each slot like a binary light switch that turns on or off (for team A or team B).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we require that each team needs 1 or more players, then we'd have to eliminate these cases:
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As you can see, there isn't a need to involve the nCr combination formula. \n" ); document.write( "Though as the other tutor @greenestamps indirectly pointed out, summing all the terms along any row of Pascal's Triangle will yield a power of 2. Terms inside the triangle are directly connected to the nCr combination formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 8190 \n" ); document.write( " \n" ); document.write( " |