document.write( "Question 1193360: A box of chocolates contains 10 milk chocolates, 8 dark chocolates, and 6 white chocolates. Hannisa randomly chooses a chocolate, eats it, and then randomly chooses another chocolate. What is the probability that Hannisa choose a milk chocolate, and then, a white chocolate? Show your solution. \n" ); document.write( "
Algebra.Com's Answer #825366 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "A = probability the first selection is a milk chocolate
\n" ); document.write( "A = (number of milk chocolates)/(number total)
\n" ); document.write( "A = (10)/(10+8+6)
\n" ); document.write( "A = 10/24
\n" ); document.write( "A = 5/12\r
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\n" ); document.write( "\n" ); document.write( "B = probability the second selection is a white chocolate, given event A has happened
\n" ); document.write( "B = (number of white chocolates)/(number of chocolates left)
\n" ); document.write( "B = (6)/(24-1)
\n" ); document.write( "B = 6/23\r
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\n" ); document.write( "\n" ); document.write( "A*B = probability of both events A and B occurring
\n" ); document.write( "A*B = (5/12)*(6/23)
\n" ); document.write( "A*B = (5*6)/(12*23)
\n" ); document.write( "A*B = (5*6)/(6*2*23)
\n" ); document.write( "A*B = (5)/(2*23)
\n" ); document.write( "A*B = 5/46\r
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\n" ); document.write( "\n" ); document.write( "Answer: 5/46
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