document.write( "Question 1193330: If sinA = cosB, compute csc(A+B). \n" ); document.write( "
Algebra.Com's Answer #825357 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: 1\r
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\n" ); document.write( "\n" ); document.write( "Reason:\r
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\n" ); document.write( "\n" ); document.write( "If A+B = 90, then cos(A) = sin(B), and vice versa.
\n" ); document.write( "We can also say sin(A) = cos(B) when A+B = 90.
\n" ); document.write( "This can be visually proven by drawing out a right triangle with acute angles A and B. I'll leave this proof for the student to carry out.\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( "csc(A+B) = 1/sin(A+B) = 1/sin(90) = 1/1 = 1
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