document.write( "Question 1193296: 2|3x-4|-3|2x+1|<7
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Algebra.Com's Answer #825313 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The behavior of the absolute value function changes at the two points where the absolute value expressions are equal to 0. \n" ); document.write( "3x-4=0 --> x=4/3 \n" ); document.write( "2x+1=0 --> x=-1/2 \n" ); document.write( "Those two values of x divide the domain into three intervals: x less than -1/2, x between -1/2 and 4/3, and x greater than 4/3. Look for solutions in each of those intervals. \n" ); document.write( "(1) x less than -1/2.... \n" ); document.write( "On this interval, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That inequality is clearly never true; so there are no solutions in this interval. \n" ); document.write( "(2) x between -1/2 and 4/3.... \n" ); document.write( "On this interval, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=-1/6 is in this interval, so part of the solution set is x between -1/6 and x=4/3 \n" ); document.write( "(3) x greater than 4/3.... \n" ); document.write( "On this interval, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That inequality is always true, so the entire interval x greater than 4/3 is part of the solution set. \n" ); document.write( "ANSWER: The solution set is (-1/6,infinity) \n" ); document.write( "A graph confirms that answer: \n" ); document.write( " \n" ); document.write( "The value of the absolute value function (red) is less than 7 (green) everywhere to the right of x=-1/6. \n" ); document.write( " \n" ); document.write( " |