document.write( "Question 113449: I need help with my sons Algebra II, it has been many years...\r
\n" ); document.write( "\n" ); document.write( "Solve the inequality algebraically\r
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\n" ); document.write( "\n" ); document.write( "x 2 -3x-4 < 0 (that is x squared)
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Algebra.Com's Answer #82531 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2+-+3x+-+4+%3C+0\"
\n" ); document.write( "\"%28x+-+4%29%28x+%2B+1%29+%3C+0\"
\n" ); document.write( "OK, I've got two things multiplied together giving me less than zero
\n" ); document.write( "which means negative. This is like
\n" ); document.write( "\"a%2Ab+%3C+0\"
\n" ); document.write( "Here are the possibilities:
\n" ); document.write( "(+)*(+) = +
\n" ); document.write( "(-)*(-) = +
\n" ); document.write( "(+)*(-) = -
\n" ); document.write( "(-)*(+) = -
\n" ); document.write( "I don't want the 1st two cases, only the 2nd two.
\n" ); document.write( "How do I make (x + 1) negative? By making x less than -1
\n" ); document.write( "\"x+%3C+-1\"
\n" ); document.write( "But if \"x+%3C+-1\", (x - 4) ends up being negative, too and I get
\n" ); document.write( "the case (-)*(-) = +, and I don't want that
\n" ); document.write( "So, I'll choose x so that (x - 4) is negative
\n" ); document.write( "\"x+%3C+4\" makes it negative, but I want (x + 1) to stay positive, too
\n" ); document.write( "(x + 1) stays positive when \"x+%3E+-1\"
\n" ); document.write( "Now I combine these
\n" ); document.write( "\"-1+%3C+x+%3C+4\"
\n" ); document.write( "Notice I only can use the case (-)*(+) = -
\n" ); document.write( "Hope you can follow this & hope I got it right, too
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