document.write( "Question 113447This question is from textbook
\n" ); document.write( ": In a poker game, two people begin with equal sums of money. When the game ended, the loser had lost $50 more than a quarter of his money and the winner had twice as much money as the loser. How much money did each person have at the end of the game? \n" ); document.write( "
Algebra.Com's Answer #82530 by edjones(8007)\"\" \"About 
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Let x be the amt. each started with.
\n" ); document.write( "The loser lost x/4+50.
\n" ); document.write( "Combined holdings always total 2x.
\n" ); document.write( "x-(x/4+50)+2(x-(x/4+50))=2x
\n" ); document.write( "x-x/4-50+2(x-x/4-50)=2x
\n" ); document.write( "x-x/4-50+2x-2x/4-100=2x
\n" ); document.write( "4x-x-200+8x-2x+-400=8x multiply each side by 4 to eliminate fractions.
\n" ); document.write( "9x-600=8x
\n" ); document.write( "x=$600 what they each started with.
\n" ); document.write( "Loser had 600-(600/4+50)
\n" ); document.write( "=600-(150+50)
\n" ); document.write( "=600-200=$400.
\n" ); document.write( "The winner had 2*400=$800.
\n" ); document.write( "Ed
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