document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193213>Question 1193213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a) Past  records  indicate  that  the  probability  of  online  retail  orders  that  turn  out  to  be  fraudulent  is <BR>\n" );
document.write( "0.06. Suppose that, on a given day, 10 online retail orders are placed. Assume that the number of <BR>\n" );
document.write( "online retail orders that turn out to be fraudulent is distributed as a binomial random variable. <BR>\n" );
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document.write( "I. What are the mean and standard deviation of the number of online retail orders that turn out to <BR>\n" );
document.write( "be fraudulent? <BR>\n" );
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document.write( "II. What is the probability that zero online retail orders will turn out to be fraudulent? <BR>\n" );
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document.write( "III. What  is  the  probability  that  greater  than or  equal  two  online  retail  order  will  turn  out  to  be <BR>\n" );
document.write( "fraudulent? \r<BR>\n" );
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document.write( "b) According to the recent research 52% of American adults own tablets. If you survey 7 American <BR>\n" );
document.write( "adults. Find the probability of <BR>\n" );
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document.write( "I. Four will own a tablet <BR>\n" );
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document.write( "II. No-one own tablet <BR>\n" );
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document.write( "III. At least two will own a tablet  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825294 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean is np=10*0.06=0.6<BR>\n" );
document.write( "variance is np(1-p)=0.6*0.94=0.504<BR>\n" );
document.write( "sd is sqrt (V)=0.701<BR>\n" );
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document.write( "0 are fraudulent mean that 10 are not=0.94^10=0.5386<BR>\n" );
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document.write( "1 is fraudulent is 10C1*0.06*0.94^9=0.3438<BR>\n" );
document.write( "The sum of p(0) and p(1) is 0.8824<BR>\n" );
document.write( ">=2 is 1- the above sum or 0.1176, the answer<BR>\n" );
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document.write( "4 will own is 7C4*0.52^4*0.48^3=0.2830<BR>\n" );
document.write( "no one will is 0.48^7=0.0059<BR>\n" );
document.write( "1 will is 7C1*0.48^1*0.52^6=0.0664<BR>\n" );
document.write( "the last two sum to 0.0723<BR>\n" );
document.write( "the complement is probability 0.9277, and that is 2 or more, the answer. </SPAN>\n" );
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