document.write( "Question 1193226: A random sample of 50 four-year-old’s attending day care centers provided a yearly tuition average of $3987 and the population standard deviation of $630. Find the 90% confidence interval of the true mean.
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Algebra.Com's Answer #825293 by Boreal(15235)\"\" \"About 
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90% half-interval is z(0.95)*630/sqrt(50)
\n" ); document.write( "=1.645*630/sqrt(50)
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\n" ); document.write( "($3840.44, $4133.46)
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