document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193218>Question 1193218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Air is being pumped into a spherical balloon at a rate of 100cm3/min. Determined the rate at which the radius of the balloon is increasing when the radius of the balloon is 10cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825227 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Air is being pumped into a spherical balloon at a rate of 100cm3/min. Determined the rate at which the radius of the balloon is increasing when the radius of the balloon is 10cm?<BR>\n" );
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document.write( "V = 4pi*r^3/3<BR>\n" );
document.write( "dV/dt = 4pi*r^2*dr/dt = 100<BR>\n" );
document.write( "dr/dt = 25/(pi*r^2) = 1/(4pi) cm/minute<BR>\n" );
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document.write( "This solution ignores physical properties such as changes in temperature and pressure of the gas. </SPAN>\n" );
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