document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193037>Question 1193037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For a quadrilateral ABCD, the measures of its angles are given below.<BR>\n" );
document.write( "m∠A = (x + 14)°<BR>\n" );
document.write( "m∠B = (2(x + 2))°<BR>\n" );
document.write( "m∠C =<BR>\n" );
document.write( "3/2<BR>\n" );
document.write( "x − 13<BR>\n" );
document.write( "°<BR>\n" );
document.write( "m∠D =<BR>\n" );
document.write( "7/3<BR>\n" );
document.write( "x − 14<BR>\n" );
document.write( "°Find x.<BR>\n" );
document.write( "then, Find the measure of each angle (in degrees) of ABCD.<BR>\n" );
document.write( "I'm not sure where to even start here. here's what I got so far: x+14+2x+4=360..and x+10+2x=360...so x+10=360..and i got 36<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825180 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "For a quadrilateral ABCD, the measures of its angles are given below.<BR>\n" );
document.write( "m∠A = (x + 14)°<BR>\n" );
document.write( "m∠B = (2(x + 2))°<BR>\n" );
document.write( "m∠C =<BR>\n" );
document.write( "3/2<BR>\n" );
document.write( "x − 13<BR>\n" );
document.write( "°<BR>\n" );
document.write( "m∠D =<BR>\n" );
document.write( "7/3<BR>\n" );
document.write( "x − 14<BR>\n" );
document.write( "°Find x.<BR>\n" );
document.write( "then, Find the measure of each angle (in degrees) of ABCD.<BR>\n" );
document.write( "I'm not sure where to even start here. here's what I got so far: x+14+2x+4=360..and x+10+2x=360...so x+10=360..and i got 36<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">The answer depends on whether the given angles are: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28matrix%281%2C7%2C+%28x+%2B+14%29%5Eo%2C+%22%2C%22%2C+2%28x+%2B+2%29%5Eo%2C+%22%2C%22%2C+%283%2F2%29x+-+13%2C+%22%2C%22%2C+%287%2F3%29x+-+14%29%2C+highlight%28OR%29%2C+matrix%281%2C7%2C+%28x+%2B+14%29%5Eo%2C+%22%2C%22%2C+2%28x+%2B+2%29%5Eo%2C+%22%2C%22%2C+%283%2F2%29%28x+-+13%29%2C+%22%2C%22%2C+%287%2F3%29%28x+-+14%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );