document.write( "Question 1193145: Cabrina and Dabney are attending a conference. After the conference, Cabrina drives home to Boise at an average speed of 75 miles per hour and Dabney drives home to Portland at an average speed of 60 miles per hour. If the sum of their driving times is 10.1 hours and if the sum of the distances driven is 711 miles, determine the time each woman spent driving home. \n" ); document.write( "
Algebra.Com's Answer #825150 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Cabrina and Dabney are attending a conference. \n" ); document.write( " After the conference, Cabrina drives home to Boise at an average speed of 75 miles per hour and Dabney drives home to Portland at an average speed of 60 miles per hour. \n" ); document.write( " If the sum of their driving times is 10.1 hours and if the sum of the distances driven is 711 miles, determine the time each woman spent driving home. \n" ); document.write( ": \n" ); document.write( "let t = C's driving time \n" ); document.write( "the total time is 10.1 hrs, therefore \n" ); document.write( "(10.1-t) = D's driving time \n" ); document.write( ": \n" ); document.write( "Write a dist equation, dist. speed * time \n" ); document.write( "C's dist + D's dist = 711 mi \n" ); document.write( "60t + 75(10.1-t) = 711 \n" ); document.write( "60t + 757.5 - 75t = 711 \n" ); document.write( "60t - 75t = 711 - 757.5 \n" ); document.write( "-15t = -46.5 \n" ); document.write( "t = -46.5/-15 \n" ); document.write( "t = 3.1 hrs is C's travel time \n" ); document.write( "then \n" ); document.write( "10.1-3.1 = 7 hr is D's travel time \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the distances each traveled \n" ); document.write( "60*3.1 = 186 mi \n" ); document.write( "75 * 7 = 525 mi \n" ); document.write( "----------------- \n" ); document.write( "total dis 711 mi\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |