document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113154>Question 113154</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/091809190x/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Having a real hard time with this...please help!\r<BR>\n" );
document.write( "\n" );
document.write( "Solve system of equation word problem but either addition method or substitution method.\r<BR>\n" );
document.write( "\n" );
document.write( "George has two investments that yield a total of $185.60 in annual interest. The amount invested at 8% is $320 less than twice the amount invested at 6%. How much is invested at each rate?\r<BR>\n" );
document.write( "\n" );
document.write( "Amount invested at 8% _________<BR>\n" );
document.write( "Amount invested at 6% _________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82513 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve system of equation word problem but either addition method or substitution method.<BR>\n" );
document.write( "George has two investments that yield a total of $185.60 in annual interest. The amount invested at 8% is $320 less than twice the amount invested at 6%. How much is invested at each rate? <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let x = amt invested at 6%; Let y = amt invested at 8$<BR>\n" );
document.write( ":<BR>\n" );
document.write( "It says,<BR>\n" );
document.write( "\" The amount invested at 8% is $320 less than twice the amount invested at 6%.\"<BR>\n" );
document.write( "Therefore:<BR>\n" );
document.write( "y = (x - 320)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "It also says,<BR>\n" );
document.write( "\"George has two investments that yield a total of $185.60 in annual interest.\"<BR>\n" );
document.write( ".06x + .08y = 185.60<BR>\n" );
document.write( ":<BR>\n" );
document.write( "We can substitute (x-320) for y in the above equation:<BR>\n" );
document.write( ".06x + .08(x-320) = 185.60<BR>\n" );
document.write( ":<BR>\n" );
document.write( ".06x + .08x - 25.6 = 185.6; multiplied what's inside the brackets<BR>\n" );
document.write( ":<BR>\n" );
document.write( ".06x + .08x = 185.60 + 25.6; added 25.6 to both sides<BR>\n" );
document.write( ":<BR>\n" );
document.write( ".14x = 211.2<BR>\n" );
document.write( ":<BR>\n" );
document.write( "x = 211.2/.14<BR>\n" );
document.write( ":<BR>\n" );
document.write( "x = $1508.57 invested at 6%<BR>\n" );
document.write( ":<BR>\n" );
document.write( "then<BR>\n" );
document.write( "1508.57 - 320 = $1188.57 invested at 8%<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "It's a good idea to check our solution in the original interest equation:<BR>\n" );
document.write( ".06(1508.57) + .08(1188.57) = <BR>\n" );
document.write( "  90.51  +  95.09  = 185.60<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Did this help you understand this?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );