document.write( "Question 1193124: A square is named ABCD point E lies on side
\n" ); document.write( "DC. If AB = 16 and AE = 20, find BE.
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Algebra.Com's Answer #825119 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Diagram:
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\n" ); document.write( "\n" ); document.write( "Focus on triangle ADE
\n" ); document.write( "Use the pythagorean theorem to find x.
\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"16%5E2+%2B+x%5E2+=+20%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"256+%2B+x%5E2+=+400\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+400-256\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+144\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%28144%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+12\"
\n" ); document.write( "Segment DE is 12 units long.
\n" ); document.write( "That makes EC = 16 - x = 16-12 = 4 units long.\r
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\n" ); document.write( "\n" ); document.write( "Now move onto triangle BEC.
\n" ); document.write( "We'll use the pythagorean theorem again.
\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+sqrt%28a%5E2+%2B+b%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+sqrt%2816%5E2+%2B+4%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+sqrt%28256+%2B+16%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+sqrt%28272%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+16.492423\"
\n" ); document.write( "Segment BE is exactly \"sqrt%28272%29\" units long which is approximately 16.492423
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