document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113412>Question 113412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My teacher gave me this problem in a review packet and I can't figure it out. It's probably very simple but I seem to be missing something. It reads...\r<BR>\n" );
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document.write( "There are 8 women for every 3 men at an inspiring teacher conference. If there are 680 more women than men, how many teachers are there total? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82511 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let y=number of men, y+680=number of women<BR>\n" );
document.write( "(y+680)/y=8/3 Proportion<BR>\n" );
document.write( "3(y+680)=8y multiply 3y times each side to eliminate fractions.<BR>\n" );
document.write( "3y+2040=8y<BR>\n" );
document.write( "5y=2040 subtract 3y from each side.<BR>\n" );
document.write( "y=408 men<BR>\n" );
document.write( "408+680=1088 women<BR>\n" );
document.write( "1088+408=1496 teachers<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "408/1088=3/8<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
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