document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1192875>Question 1192875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> lb) What is the probability that the sample mean is between 14.75 and 22.5?\r<BR>\n" );
document.write( "\n" );
document.write( "1. A soda machine dispenses soda into 16-ounce cups. Tests shows that the actual amount of soda dispensed has a mean of 15.85 oz and a standard deviation of 9.5 oz. A sample of 12 cups is taken.\r<BR>\n" );
document.write( "\n" );
document.write( "la) What is the probability that the sample mean is at most 11.25?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825104 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the first is z between (14.75-15.85)/9.5/sqrt(12)=-0.401 and (22.5-15.85)/9.5/sqrt(12)=2.74 That probability is 0.6527<BR>\n" );
document.write( "-<BR>\n" );
document.write( "That is z< (11.25-15.85)/9.5/sqrt(12)=-4.60*sqrt(12)/9.5=-1.68<BR>\n" );
document.write( "probability is 0.0465 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );