document.write( "Question 1193084: Leo swims at 2 miles per hour in still water. After he swims down a river a quarter of a mile, returning takes three times as long as swimming downstream. Find the rate of the current. \n" ); document.write( "

Algebra.Com's Answer #825057 by josgarithmetic(39630) $\"\"$ $\"About$

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2 mph, Leo's speed without in a current
\n" ); document.write( "c, speed of the current\r
\n" ); document.write( "\n" ); document.write( "Upstream speed 2-c
\n" ); document.write( "Downstream speed 2+c\r
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document.write( "            SPEED      TIME                       DISTANCE\r\n" );
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document.write( "DOWN         2+c                    \r\n" );
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document.write( "UPSTR        2-c                      \r\n" );
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\n" ); document.write( "According to the description, $\"%281%2F4%29%2F%282-c%29=3%281%2F4%29%2F%282%2Bc%29\"$ , and the question asks for c.\r
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\n" ); document.write( "\n" ); document.write( "Multiply left and right side members by 4;
\n" ); document.write( " $\"1%2F%282-c%29=3%2F%282%2Bc%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"2%2Bc=3%282-c%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"2%2Bc=6-3c\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"4c=4\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28c=1%29\"$ \n" ); document.write( "

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