document.write( "Question 113395: Hello out there,I need some help with some really tough problems,I only have two of them,the first one is,Determine whether the number is rational or irrational.If it is irrational,find two consecutive integers between which its graph lies on the number line,-sqrt81.And the last one is,Determine whether sqrt 67 is rational or irrational.If it is irrational,find two consecutive integers between which its graph lies on the number line.Thanks to whoever can help. \n" ); document.write( "
Algebra.Com's Answer #82505 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "67 is not a perfect square, because \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's suppose the square root of 67 is a rational number. Then it must be \n" ); document.write( "of the form a/b, where a and b are whole numbers. Furthermore, we can \n" ); document.write( "assume that a and b don't have any common factor (otherwise we could \n" ); document.write( "just divide the numerator and denominator by the common factor).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means that a squared is a multiple of 67. Now you can easily see \n" ); document.write( "that to get a number that is a multiple of 67 by squaring a, a itself \n" ); document.write( "must be a multiple of 67, so \n" ); document.write( "this back into the equation, we get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we divide both sides of the equation by 67, getting\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( "\n" ); document.write( "But now we are in trouble, because we have shown that both a and b are \n" ); document.write( "multiples of 67, but we know that a and b have no common factor, since we chose \n" ); document.write( "our original assumption that \n" ); document.write( "have been wrong. Therefore, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps, \n" ); document.write( "John \n" ); document.write( " |