document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193079>Question 1193079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ▱ABCD<BR>\n" );
document.write( "m∠A = (2x + 4)°<BR>\n" );
document.write( "and<BR>\n" );
document.write( "m∠B = (3x − 34)°.<BR>\n" );
document.write( "i found x which i got 42.<BR>\n" );
document.write( "Find the measure of each angle (in degrees) of<BR>\n" );
document.write( "▱ABCD.<BR>\n" );
document.write( "m∠A =<BR>\n" );
document.write( "°<BR>\n" );
document.write( "m∠B =<BR>\n" );
document.write( "°<BR>\n" );
document.write( "m∠C =<BR>\n" );
document.write( "°<BR>\n" );
document.write( "m∠D =<BR>\n" );
document.write( "° </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825026 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You have solved correctly for x.<br><BR>\n" );
document.write( "Angles A and B are supplementary, so<br><BR>\n" );
document.write( "(2x+4)+(3x-34)=180<BR>\n" );
document.write( "5x-30=180<BR>\n" );
document.write( "5x=210<BR>\n" );
document.write( "x=42<br><BR>\n" );
document.write( "Now plug in x=42 to find the measure of angle A (2x+4) and angle B (3x-34).<br><BR>\n" );
document.write( "Then, since this is a parallelogram, the measure of angle C is the same as angle A, and the measure of angle D is the same as angle B.<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );