document.write( "Question 1193079: ▱ABCD
\n" ); document.write( "m∠A = (2x + 4)°
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\n" ); document.write( "m∠B = (3x − 34)°.
\n" ); document.write( "i found x which i got 42.
\n" ); document.write( "Find the measure of each angle (in degrees) of
\n" ); document.write( "▱ABCD.
\n" ); document.write( "m∠A =
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\n" ); document.write( "m∠B =
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\n" ); document.write( "m∠C =
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\n" ); document.write( "m∠D =
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Algebra.Com's Answer #825024 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
I guess you have a parallelogram. If so than \"m+%3CA+=m+%3CC\" and \"m+%3CB+=m+%3C+D\"\r
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"m\" <\"A+=+%282x+%2B+4%29\"°
\n" ); document.write( "and
\n" ); document.write( "\"m\" < \"B+=+%283x+-34%29\"°.\r
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\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"m+\"< \"A+=+180\"- \"m\" < \"B+\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+4=180-%283x+-34%29\"\r
\n" ); document.write( "\n" ); document.write( "\"5x+=+210+\"\r
\n" ); document.write( "\n" ); document.write( "\"x=42\"\r
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\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"m\"<\"A+=+%282%2A42+%2B+4%29+=88\"°=>\"m\"<\"C=88\"°\r
\n" ); document.write( "\n" ); document.write( "\"m\"< \"B+=+%283%2A42+-34%29=92\"°=>\"m\"< \"D=92\"°
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