document.write( "Question 1193047: The Z score of the sample mean on the distribution of means is:
\n" ); document.write( "A) different from a normal Z score because an estimated population standard deviation is used
\n" ); document.write( "B) smaller than normal due to the reduced variance in the distribution of means
\n" ); document.write( "C) conceptually similar to creating a Z score from a raw score
\n" ); document.write( "D) equivalent to the sample mean divided by the population variance
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Algebra.Com's Answer #825011 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i would say B.
\n" ); document.write( "the formula for a z-score of an individual element is z = (x - m) / sd
\n" ); document.write( "the formula for a z-score of the mean of a sample of n elements is z = (x - m) / (sd / sqrt(n)).
\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the mean
\n" ); document.write( "sd is the standard deviation of an individual element in the distribution of elements.
\n" ); document.write( "(sd / sqrt(n)) is the standard deviation of the sample means in a distribution of sample means.
\n" ); document.write( "here's a reference on the subject.
\n" ); document.write( "https://onlinestatbook.com/2/sampling_distributions/samp_dist_mean.html
\n" ); document.write( "here's another.
\n" ); document.write( "http://matcmath.org/textbooks/engineeringstats/distribution-of-sample-means/\r
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