document.write( "Question 113366: Find three positive consecutive even integers such that the product of the first and second is 8 more than 38 times the third. \n" ); document.write( "
Algebra.Com's Answer #82497 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
X, X+2, X+4 ARE THE 3 POSITIVE CONSECUTIVE INTEGERS.
\n" ); document.write( "X(X+2)=8+38(X+4)
\n" ); document.write( "X^2+2X=8+38X+152
\n" ); document.write( "X^2+2X-38X-8-152=0
\n" ); document.write( "X^2-36X-160=0
\n" ); document.write( "(X-40)(X+4)=0
\n" ); document.write( "X-40=0
\n" ); document.write( "X=40 ANSWER FOR THE FIRST INTEGER.
\n" ); document.write( "40+2=42 FOR THE SECOND INTEGER.
\n" ); document.write( "40+4=44 FOR THE THIRD INTEGER.
\n" ); document.write( "PROOF
\n" ); document.write( "40*42=8+38*44
\n" ); document.write( "1680=8+1672
\n" ); document.write( "1680=1680
\n" ); document.write( "
\n" );