document.write( "Question 113366: Find three positive consecutive even integers such that the product of the first and second is 8 more than 38 times the third. \n" ); document.write( "
Algebra.Com's Answer #82497 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X, X+2, X+4 ARE THE 3 POSITIVE CONSECUTIVE INTEGERS. \n" ); document.write( "X(X+2)=8+38(X+4) \n" ); document.write( "X^2+2X=8+38X+152 \n" ); document.write( "X^2+2X-38X-8-152=0 \n" ); document.write( "X^2-36X-160=0 \n" ); document.write( "(X-40)(X+4)=0 \n" ); document.write( "X-40=0 \n" ); document.write( "X=40 ANSWER FOR THE FIRST INTEGER. \n" ); document.write( "40+2=42 FOR THE SECOND INTEGER. \n" ); document.write( "40+4=44 FOR THE THIRD INTEGER. \n" ); document.write( "PROOF \n" ); document.write( "40*42=8+38*44 \n" ); document.write( "1680=8+1672 \n" ); document.write( "1680=1680 \n" ); document.write( " |