document.write( "Question 1193021: State two different ways to determine the number of zeros of the function \r
\n" ); document.write( "\n" ); document.write( "f(x)=2(x+1)^2 -6
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Algebra.Com's Answer #824966 by greenestamps(13215)\"\" \"About 
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\n" ); document.write( "Technically, it is a polynomial of degree 2, so it has 2 zeros.

\n" ); document.write( "If you mean real zeros, then....

\n" ); document.write( "(1) Convert the equation to standard form \"ax%5E2%2Bbx%2Bc=0\" and look at the discriminant \"b%5E2-4ac\". There are 2 zeros if the discriminant is positive, 1 zero if it is 0, and no (real) zeros if it is negative.

\n" ); document.write( "(2) The equation as given is in vertex form. The vertex is (-1,-6) and the parabola opens upward, so there are 2 real zeros.

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