document.write( "Question 1192996: joy invested a certain amount at 9%, twice that amount at 10%, and three times that amount at 11%. find the amount invested at each rate if the total yearly income from the three investments was Php27,900.00. What is the amount of the investment at 10% \n" ); document.write( "

Algebra.Com's Answer #824945 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "The amounts invested at 9%, 10%, and 11% were x, 2x, and 3x, respectively.

\n" ); document.write( "So 1/6 of the total was invested at 9%; 2/6 = 1/3 at 10%, and 3/6 = 1/2 at 11%.

\n" ); document.write( "The average percent return on the investment was $\"%289%281%29%2B10%282%29%2B11%283%29%29%2F%281%2B2%2B3%29\"$ , or 10 1/3%. As a fraction that percentage is $\"%2810%2B1%2F3%29%2F100+=+%2831%2F3%29%2F100+=31%2F300\"$

\n" ); document.write( "27,900 return at a rate of 10 1/3% means the amount invested was $\"27900%2F%2831%2F300%29=27900%28300%2F31%29=%2827900%2F31%29%2A300=900%2A300=270000\"$

\n" ); document.write( "ANSWERS:
\n" ); document.write( "1/6 of Php270,000 = Php45,000 at 9%
\n" ); document.write( "1/3 of Php270,000 = Php90,000 at 10%
\n" ); document.write( "1/2 of Php270,000 = Php135,000 at 11%

\n" ); document.write( "CHECK:
\n" ); document.write( ".09(45000)+.10(90000)+.11(135000)=4050+9000+14850=27900

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