document.write( "Question 113363: please help me with this problem.
\n" ); document.write( "x^3/2=10.42
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Algebra.Com's Answer #82492 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I presume you want to solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E%283%2F2%29=125\". This is equivalent to \"%28sqrt%28x%29%29%5E3=125\". In general, \"x%5E%28a%2Fb%29=%28root%28b%2Cx%29%29%5Ea\"\r
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\n" ); document.write( "\n" ); document.write( "So the first thing to do is to take the cube root of both sides of the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"root%283%2Cx%5E%283%2F2%29%29=root%283%2C125%29\"
\n" ); document.write( "\"sqrt%28x%29=5\" (because 5 X 5 X 5 = 125, and because \"x%5E%281%2F2%29=sqrt%28x%29\")\r
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\n" ); document.write( "\n" ); document.write( "Then you need to square both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x%29%29%5E2=5%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=25\". Done.\r
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\n" ); document.write( "\n" ); document.write( "By the way, the steps I used don't have to be done in that order. We could have squared 125 to get 15625 and then taken the cube root of 15625 to get 25. I did it the way I did because the numbers stayed smaller so the arithmetic was easier.\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps,
\n" ); document.write( "John
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