document.write( "Question 1192963: Three resistors, of 40 Ω, 60 Ω, and 120 Ω are connected in parallel and this parallel group is connected with 15 Ω in series with 25 Ω. The whole system is then connected to a 120 V source. Determine (a) the I in 25 Ω, (b) the potential drop across the parallel group, (c) the potential across the 25 Ω, (d) the I in the 60 Ω, and (e) the I in 40 Ω. \n" ); document.write( "

Algebra.Com's Answer #824908 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "Three resistors, of 40 Ω, 60 Ω, and 120 Ω are connected in parallel and this parallel group
\n" ); document.write( "is connected with 15 Ω in series with 25 Ω. The whole system is then connected to a 120 V source.
\n" ); document.write( "Determine (a) the I in 25 Ω, (b) the potential drop across the parallel group,
\n" ); document.write( "(c) the potential across the 25 Ω, (d) the I in the 60 Ω, and (e) the I in 40 Ω.
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document.write( "Resistance of the parallel group is   =  =  =  = 20 Ω.\r\n" );
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document.write( "So, now we can consider the circuit as a series of 20 Ω, 15 Ω and 25 Ω with the combined resistance of (20 Ω + 15 Ω + 25 Ω) = 60 Ω.\r\n" );
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document.write( "Hence, the electric current  \" I \"  through 25 Ω (a) is  = 2 amperes.\r\n" );
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document.write( "        Thus question (a) is answered.\r\n" );
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document.write( "Potential drop across the parallel group is 20*2 = 40 V (b); across the 25 Ω is 25*2 = 50 V (c).\r\n" );
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document.write( "        Thus questions (b) and (d) are answered.\r\n" );
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