document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16971>Question 16971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Graph<BR>\n" );
document.write( "How can I solve y=2x -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8249 by </B><A HREF=/tutors/aboutme.mpl?userid=Ms+Ladii><B>Ms Ladii(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ms+Ladii><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8249\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  First you need to rebember the slope formula<BR>\n" );
document.write( "y=mx+b<BR>\n" );
document.write( " In your problem you have to graph y=2x-3<BR>\n" );
document.write( "so: y=mx+b<BR>\n" );
document.write( "    y=2x-3<BR>\n" );
document.write( " you have to find m the slope and b<BR>\n" );
document.write( " y=mx+b<BR>\n" );
document.write( " y=2x-b<BR>\n" );
document.write( "Slope(m)= 2<BR>\n" );
document.write( "      b= -3<BR>\n" );
document.write( "So you start at piont negative 3 (-3)<BR>\n" );
document.write( "and move the point up 2 and right 1<BR>\n" );
document.write( "making a diagonal line that slants towards the right </SPAN>\n" );
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