document.write( "Question 1192919: Hi, I am confused on how to do this one.
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document.write( "|x-3|+4|x+2|>17 \n" );
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Algebra.Com's Answer #824862 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "The critical points of the function on the left (where the behavior of the function changes) are at x=3 and x=-2. To solve the inequality, look for solutions on three intervals: (1) -infinity to -2; (2) -2 to 3; and (3) 3 to infinity. \n" ); document.write( "(1) -infinity to -2.... \n" ); document.write( "On this interval, |x-3| = -x+3 and |x+2| = -x-2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This solution is completely within the interval we are working in, so it is part of the solution to the inequality. \n" ); document.write( "ANSWER (first part): Part of the solution set is the interval (-infinity,-4,4) \n" ); document.write( "(2) -2 to 3.... \n" ); document.write( "On this interval, |x-3| = -x+3 and |x+2| = x+2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In the interval from -2 to 3, the only part that is in the solution set is x>2. \n" ); document.write( "ANSWER (second part): Part of the solution set is the interval (2,3] \n" ); document.write( "(3) 3 to infinity.... \n" ); document.write( "On this interval, |x-3| = x-3 and |x+2| = x+2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This inequality is satisfied on the entire interval we are working in, so this entire interval is part of the solution set. \n" ); document.write( "ANSWER (third and last part): Part of the solution set is the interval [3,infinity). \n" ); document.write( "ANSWER: The solution set of the inequality is the union of the three solution sets we found in the three intervals: (-infinity, -4.4) U (2,infinity) \n" ); document.write( "A graph of the absolute value function (red) and the constant function 17 (green) shows the behavior of the absolute value function changing at x=-2 and x=3; and it shows the absolute value function being greater than 17 to the left of x=-4.4 and to the right of x=2. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |