document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1192903>Question 1192903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Information from the American Institute of Insurance indicates the mean amount of life insurance per household in the United States is $115,000. This distribution follows the normal distribution with a standard deviation of $37,000.\r<BR>\n" );
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document.write( "a.What is the likelihood of selecting a sample with a mean of at least $120,000? (Round your z-value to 2 decimal places and final answer to 4 decimal places.)\r<BR>\n" );
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document.write( "b.What is the likelihood of selecting a sample with a mean of more than $106,000? (\r<BR>\n" );
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document.write( "c. Find the likelihood of selecting a sample with a mean of more than $106,000 but less than $120,000. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #824840 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=824840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
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document.write( "A. z>(120000-115000)/37000=5/37 so probability is 0.4463<BR>\n" );
document.write( "B. this is z-9000/37000 or z >-9/37, probability is 0.5961<BR>\n" );
document.write( "C.This is the difference between the two or probability of 0.1498 </SPAN>\n" );
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