document.write( "Question 113350: The length of a rectangle is 3 inches more than the width. The perimeter of the rectangle is 24 inches......How do I solve this??? HELP!! \n" ); document.write( "
Algebra.Com's Answer #82484 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=W+3 \n" ); document.write( "24=2L+2W \n" ); document.write( "24=2(W+3)+2W \n" ); document.write( "24=2W+6+2W \n" ); document.write( "24=4W+6 \n" ); document.write( "4W=24-6 \n" ); document.write( "4W=18 \n" ); document.write( "W=18/4 \n" ); document.write( "W=4.5 ANSWER. \n" ); document.write( "L=4.5+3 \n" ); document.write( "L=7.5 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "24=2*4.5+2*7.5 \n" ); document.write( "24=9+15 \n" ); document.write( "24=24 \n" ); document.write( " \n" ); document.write( " |