document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113347>Question 113347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 10cm less than 3 times its width. If the perimeter of the rectangle is at most 180 cm, find the greatest possible length of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82482 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LENGTH=3W-10<BR>\n" );
document.write( "180=(3W-10)W<BR>\n" );
document.write( "180=3W^2-10W<BR>\n" );
document.write( "3W^2-10W-180=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION WE GET:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "W=(10+-SQRT[10^2-4*3*-180])/2*3<BR>\n" );
document.write( "W=(10+-SQRT100+2160])/6<BR>\n" );
document.write( "W=(10+-SQRT2260)/6<BR>\n" );
document.write( "W=(10+-47.54)/6<BR>\n" );
document.write( "W=(10+47.54)/6<BR>\n" );
document.write( "W=57.54)/6<BR>\n" );
document.write( "W=9.59 ANSWER.<BR>\n" );
document.write( "W=(10-47.54)/6<BR>\n" );
document.write( "W=-37.54/6<BR>\n" );
document.write( "W=-6.26 ANSWER.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );