document.write( "Question 1192891: the numerator of a fraction is 1 less than the denominator.
\n" );
document.write( "when both numerator and denominator are increased by 2,
\n" );
document.write( "the fraction is increased 1/12`find the original fraction
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #824813 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "You must have copied this problem wrong, or your teacher or the\r\n" ); document.write( "the textbook writer made a mistake, for there is no solution. \r\n" ); document.write( "However, if 1/12 is changed to 1/9, there will be a solution. \r\n" ); document.write( "\r\n" ); document.write( "I will work a problem exactly like yours, changing 1/12 to 1/9. \r\n" ); document.write( "The problem I will work is: \n" ); document.write( "The numerator of a POSITIVE PROPER FRACTION REDUCED TO \n" ); document.write( "LOWEST TERMS is 1 less than the denominator. When both numerator \n" ); document.write( "and denominator are increased by 2, the fraction is increased by \n" ); document.write( "1/9. Find the original fraction. \r\n" ); document.write( "\r\n" ); document.write( "Let n = the denominator \n" ); document.write( "The numerator of a fraction is 1 less than the denominator. \r\n" ); document.write( "Then the numerator = n-1\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "when both numerator and denominator are increased by 2, \r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "the fraction is increased by 1/9. \r\n" ); document.write( "\n" ); document.write( " |