document.write( "Question 1192881: What is the 20th term of the sequence 0, 3, 8, 15, 24, 35, 48, . .
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Algebra.Com's Answer #824806 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I'm assuming that this is a quadratic sequence because the gap between terms 3, 5, 7, 9, 11, 13, ... are of an arithmetic sequence (common difference d = 2). \n" ); document.write( "If this assumption is not the case, then please let me know and I'll update the solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If it is quadratic, then it means you'll have something of the form \n" ); document.write( "y = ax^2+bx+c \n" ); document.write( "where x is the term number and y is the term itself.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Examples: \n" ); document.write( "(x,y) = (1,0) means the first term is 0. \n" ); document.write( "(x,y) = (2,3) means the second term is 3. \n" ); document.write( "and so on.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in (x,y) = (1,0) to find that \n" ); document.write( "y = ax^2+bx+c \n" ); document.write( "0 = a(1)^2+b(1)+c \n" ); document.write( "0 = a+b+c \n" ); document.write( "a+b+c = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then plug in x = 2 and y = 3 to get \n" ); document.write( "4a+2b+c = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And plug in x = 3 and y = 8 to get \n" ); document.write( "9a+3b+c = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The task is to solve this system of equations \n" ); document.write( "a+b+c = 0 \n" ); document.write( "4a+2b+c = 3 \n" ); document.write( "9a+3b+c = 8 \n" ); document.write( "I'll skip the steps because it's a very long process, but the punchline is that \n" ); document.write( "a = 1 \n" ); document.write( "b = 0 \n" ); document.write( "c = -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means \n" ); document.write( "y = ax^2+bx+c \n" ); document.write( "y = 1x^2+0x+(-1) \n" ); document.write( "y = x^2-1 \n" ); document.write( "represents a nice simple formula to generate any term (y) based on the term number (x).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking the formula:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in x = 1 to represent the first term \n" ); document.write( "y = x^2 - 1 \n" ); document.write( "y = 1^2 - 1 \n" ); document.write( "y = 0 \n" ); document.write( "That works out because 0 is indeed the first term\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Repeat for x = 2 \n" ); document.write( "y = x^2 - 1 \n" ); document.write( "y = 2^2 - 1 \n" ); document.write( "y = 3 \n" ); document.write( "That works out as well\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll let you check the other terms.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plugging in x = 20 will then lead you to y = 399 which is the 20th term.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Once again, this all depends on if the sequence given is quadratic in nature. \n" ); document.write( " \n" ); document.write( " |