document.write( "Question 1192867: Thaddeus and Ian start at the same location and drive in opposite​ directions, but leave at different times. When they are 575 miles​ apart, their combined travel time is 11 hours. If Thaddeus drives at a rate of 50 miles per hour and Ian drives at a rate of 55 miles per​ hour, how long had each been​ driving?
\n" ); document.write( "Thaddeus has been driving ____ ​hours, and Ian has been driving ____ hours
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Algebra.Com's Answer #824786 by ankor@dixie-net.com(22740)\"\" \"About 
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Thaddeus and Ian start at the same location and drive in opposite​ directions, but leave at different times.
\n" ); document.write( " When they are 575 miles​ apart, their combined travel time is 11 hours.
\n" ); document.write( " If Thaddeus drives at a rate of 50 miles per hour and Ian drives at a rate of 55 miles per​ hour, how long had each been​ driving?
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\n" ); document.write( "let t = T's travel time
\n" ); document.write( "the total of both times is 11 hrs, therefore
\n" ); document.write( "(11-t) = I's travel time
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\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( "T's dist + I's dist = 575 miles
\n" ); document.write( "50t + 55(11-t) = 575
\n" ); document.write( "50t + 605 - 55t = 575
\n" ); document.write( "50t - 55t = 575 - 605
\n" ); document.write( "-5t = -30
\n" ); document.write( "t = -30/-5
\n" ); document.write( "t = +6 hrs is T's travel time
\n" ); document.write( "then
\n" ); document.write( "11-6 = 5 hrs is I's travel time
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\n" ); document.write( "Check, find actual dist for each
\n" ); document.write( "6*50 = 300 mi
\n" ); document.write( "5*55 = 275 mi
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\n" ); document.write( "total d: 575\r
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