document.write( "Question 1192843: I’m 25. My father is 2 times my age. When I’ll be 50, how old is my father?express mathematically
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Algebra.Com's Answer #824760 by Theo(13342)\"\" \"About 
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your age now is 25.
\n" ); document.write( "your father's age now is 2 * 25 = 50
\n" ); document.write( "you will be 50 in 50 - 25 = 25 years.
\n" ); document.write( "your father will be 50 + 25 = 75 in 25 years.
\n" ); document.write( "when you are 50, your father will be 75.\r
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\n" ); document.write( "\n" ); document.write( "i think that, algebraically, your father's age will be 25 years more than your age.
\n" ); document.write( "algebraically that would be y = x + 25.
\n" ); document.write( "y is your father's age.
\n" ); document.write( "x is your age.\r
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\n" ); document.write( "\n" ); document.write( "when x = 25, then y = 25 + 25 = 50
\n" ); document.write( "when x = 50, then y = 50 + 25 = 75\r
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\n" ); document.write( "\n" ); document.write( "note that, when x = 25, y is also equal to 2 * x, but that only occurs when x = 25.\r
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\n" ); document.write( "\n" ); document.write( "to confirm, you have two equations that need to be solved simultaneously.
\n" ); document.write( "they are:
\n" ); document.write( "y = 2x
\n" ); document.write( "y = x + 25
\n" ); document.write( "replace y with 2x in the second equation to get:
\n" ); document.write( "2x = x + 25
\n" ); document.write( "subtract x from both sides of the equation to get:
\n" ); document.write( "2x - x = 25
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 25.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that the algebraic equation is y = x + 25.
\n" ); document.write( "y is your father's age.
\n" ); document.write( "x is your age.\r
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