document.write( "Question 1192675: Hi, I'm getting stuck, so please I need a volunteer to help me
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document.write( "here is the problem\r
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document.write( "For surgeries and serious injuries, anesthesiologists are responsible for administering anesthesia. If correct dosages are not given and monitored, it is possible patients may wake up during a procedure. Avoiding this disaster takes analysis of an anesthesia’s concentration in the bloodstream. When a concentration of an anesthesia is below 0.1 mg/L, it is no longer effective. In these two cases, you must use rational functions to model the anesthesia’s concentration in the bloodstream and determine when the patient may wake up.
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document.write( "Given a model for this patient’s concentration over time, complete the table with useful times or amounts. Use the model to determine when they may wake up. Model y =2.8x/0.4x^2+ 1.3\r
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document.write( "Fill in the table with their correct value
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document.write( "The first column represents the x values and the second column represents the y values
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document.write( "Minutes Since Dose(x) Concentration in mg/L (y)
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document.write( " 5 → ...
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document.write( " 10 → ...
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document.write( " 20 → ...
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document.write( " 30 → ...
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document.write( " 60 → ...
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document.write( " ... → 0.4
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document.write( " ... → 0.2
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document.write( " ... → 0.1
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document.write( " ... → 0.01\r
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document.write( "1)Based on the model, when will the patient wake up?\r
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document.write( "2)If the procedure lasts approximately 1 hour and thirty minutes, will additional anesthesia be required? \r
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document.write( "3)Can you determine the maximum amount of concentration that the patient had in their bloodstream? If it is over 2 mg/L, then it could be dangerous. \n" );
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Algebra.Com's Answer #824744 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! I am assuming it is y=(2.8x)/(0.4x^2+1.3). \n" ); document.write( "x=5, y=14/(10+1.3)=14/11.3=1.24 \n" ); document.write( "x=10, y=28/41.3=0.68 \n" ); document.write( "x=20, y=56/161.3=0.35 \n" ); document.write( "x=30, y=84/361.3=0.23 \n" ); document.write( "x=60, y=168/1441.3=0.117 \n" ); document.write( "- \n" ); document.write( "y=0.4=(2.8x)/(0.4x^2+1.3) \n" ); document.write( "0.16x^2+0.52=2.8x \n" ); document.write( "0.16x^2-2.8x+0.52=0 \n" ); document.write( "16x^2-280x+52=0; 4x^2-70x+13=0 \n" ); document.write( "x=17.3 min \n" ); document.write( "- \n" ); document.write( "y=0.2 \n" ); document.write( "0.08x^2+0.26=2.8x \n" ); document.write( "0.08x^2-2.8x+0.26=0 \n" ); document.write( "8x^2-280x+26=0; 4x^2-140x+13=0 \n" ); document.write( "x=34.91 min \n" ); document.write( "- \n" ); document.write( "y=0.1 \n" ); document.write( "0.04x^2+0.13=2.8x \n" ); document.write( "0.04x^-2.8x+0.13=0 \n" ); document.write( "4x^2-280x+13=0 \n" ); document.write( "x=70 min. \n" ); document.write( "An hour and a half would be too long. The minimum is reached in 1h10m \n" ); document.write( "- \n" ); document.write( "y=0.01 \n" ); document.write( "0.004x^2-2.8x+0.013=0, 695 minutes\r \n" ); document.write( "\n" ); document.write( "- \n" ); document.write( "Substitute 2 for y \r \n" ); document.write( "\n" ); document.write( "2=(2.8x)/(0.4x^2+1.3) \n" ); document.write( "0.8x^2+2.6=2.8x \n" ); document.write( "0.8x^2-2.8x+2.6=0 \n" ); document.write( "8x^2-28x+26=0 \n" ); document.write( "4x^2-7x+13=0, and this has complex roots, so it does not reach 2 mg/l\r \n" ); document.write( "\n" ); document.write( "Take the derivative and it is y'=(0.4x^2+1.3)*2.8-(2.8x)(0.8x)/(0.4x^2+1.3)^2 \n" ); document.write( "set y'=0 and multiply through by the denominator, which disappears \n" ); document.write( "so 1.12x^2+3.64=2.24x^2 and 1.12x^2=3.64 and x=1.80 min maximum\r \n" ); document.write( "\n" ); document.write( "- \n" ); document.write( "The horizontal lines are y=0.1,0.2,0.4,0.6,0.8 mg/l \n" ); document.write( " |