document.write( "Question 1192821: Simplify Completely, keep all answers and work in radical form
\n" ); document.write( "5*sqrt(128x^3)+4*sqrt(98x^2)-3x*sqrt(162x)
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Algebra.Com's Answer #824737 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Notice that 128 = 64*2 showing that 64 is the largest perfect square factor of 128.
\n" ); document.write( "Similarly, x^2 is the largest perfect square factor of x^3\r
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\n" ); document.write( "\n" ); document.write( "We can rewrite 128x^3 into 64x^2*2x to be able to perform this simplification
\n" ); document.write( "\"sqrt%28128x%5E3%29+=+sqrt%2864x%5E2%2A2x%29\"
\n" ); document.write( "\"sqrt%28128x%5E3%29+=+sqrt%2864x%5E2%29%2Asqrt%282x%29\" Use the rule that sqrt(A*B) = sqrt(A)*sqrt(B)
\n" ); document.write( "\"sqrt%28128x%5E3%29+=+sqrt%28%288x%29%5E2%29%2Asqrt%282x%29\"
\n" ); document.write( "\"sqrt%28128x%5E3%29+=+8x%2Asqrt%282x%29\"
\n" ); document.write( "Such that \"x+%3E=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Through similar logic, we can also say:
\n" ); document.write( "\"sqrt%2898x%5E2%29+=+sqrt%2849x%5E2%2A2%29\"
\n" ); document.write( "\"sqrt%2898x%5E2%29+=+sqrt%2849x%5E2%29%2Asqrt%282%29\"
\n" ); document.write( "\"sqrt%2898x%5E2%29+=+sqrt%28%287x%29%5E2%29%2Asqrt%282%29\"
\n" ); document.write( "\"sqrt%2898x%5E2%29+=+7x%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "And also,
\n" ); document.write( "\"sqrt%28162x%29+=+sqrt%2881%2A2x%29\"
\n" ); document.write( "\"sqrt%28162x%29+=+sqrt%2881%29%2Asqrt%282x%29\"
\n" ); document.write( "\"sqrt%28162x%29+=+9%2Asqrt%282x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Use the three results we got earlier above to simplify the given expresdsion like so
\n" ); document.write( "\"5%2Asqrt%28128x%5E3%29%2B4%2Asqrt%2898x%5E2%29-3x%2Asqrt%28162x%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5%2A8x%2Asqrt%282x%29%2B4%2A7x%2Asqrt%282%29-3x%2A9%2Asqrt%282x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"40x%2Asqrt%282x%29%2B28x%2Asqrt%282%29-27x%2Asqrt%282x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"40x%2Asqrt%282x%29-27x%2Asqrt%282x%29%2B28x%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2840x-27x%29%2Asqrt%282x%29%2B28x%2Asqrt%282%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"13x%2Asqrt%282x%29%2B28x%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( "\"5%2Asqrt%28128x%5E3%29%2B4%2Asqrt%2898x%5E2%29-3x%2Asqrt%28162x%29\" simplifies to \"13x%2Asqrt%282x%29%2B28x%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "Or we can say
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\n" ); document.write( "only when \"x+%3E=+0\"
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